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Question:

Math Help.!!!!!!!!!!?
Math Help.!!!!!!!!!!?
Math Help.!!!!!!!!!!? Solve each linear system. Verify each solution by substituting like 20/3, how did they get that into both equations.

x- y = 8 and x + 2y = 4
I don't understand. The answer comes to something the coordinates of your solution
.

http://answers.yahoo.com/question/?qid=20081121162435AADi56G

Answers:

Best Answer
x - y = 8
x + 2y = 4

Multiply the first equation by 2:
2x - 2y = 16

Add it to the second equation:
(2x - 2y) + (x + 2y) = 16 + 4
3x = 20
x = 20/3

To find y, simply plug the x=20/3 into any of the equations and then solve for y
to get y = -4/3

Subtract the equations.

x-y=8
x+2y=4

-3y = 4

y = -4/3

Substitute to find x.

x - y = 8
x + 4/3 = 8

x = 20/3

x-y = 8
x = 8 +y plug into second equ.
(8+y) +2y =4
8+3y =4
3y = -4
y = -4/3 plug into first equ.
x- (-4/3) =8
x+(4/3) = 8
x = 8- (4/3)
x = (24/3) - (4/3)
x = 20/3

What they did was to set first equation to solve for x,

x = y+8

Then they put that into the the first equation equal to y

y+8+2y = 4
y = -4/3

Then they put this into the second equation to solve for
x

x = 4/3 = 8
x = 8 - 4/3
x = 20/3

Have a good day!

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